Base | Representation |
---|---|
bin | 10001111100011100010… |
… | …101111101000011111010 |
3 | 11100212221000202221210012 |
4 | 101330130111331003322 |
5 | 130200423032144010 |
6 | 2342254223421522 |
7 | 155043065446043 |
oct | 21743425750372 |
9 | 4325830687705 |
10 | 1233131131130 |
11 | 435a714152a8 |
12 | 17aba51548a2 |
13 | 8c38c587902 |
14 | 439807518ca |
15 | 2212365c005 |
hex | 11f1c57d0fa |
1233131131130 has 32 divisors (see below), whose sum is σ = 2224427336064. Its totient is φ = 492188187456.
The previous prime is 1233131131123. The next prime is 1233131131151. The reversal of 1233131131130 is 311311313321.
It is a super-2 number, since 2×12331311311302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1233131131096 and 1233131131105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22969499 + ... + 23023121.
It is an arithmetic number, because the mean of its divisors is an integer number (69513354252).
Almost surely, 21233131131130 is an apocalyptic number.
1233131131130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1233131131130 is a deficient number, since it is larger than the sum of its proper divisors (991296204934).
1233131131130 is a wasteful number, since it uses less digits than its factorization.
1233131131130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58550.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1233131131130 its reverse (311311313321), we get a palindrome (1544442444451).
The spelling of 1233131131130 in words is "one trillion, two hundred thirty-three billion, one hundred thirty-one million, one hundred thirty-one thousand, one hundred thirty".
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