123313122001499 has 2 divisors, whose sum is σ = 123313122001500. Its totient is φ = 123313122001498.

The previous prime is 123313122001481. The next prime is 123313122001501. The reversal of 123313122001499 is 994100221313321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123313122001499 - 2¹⁶ = 123313121935963 is a prime.

It is a super-2 number, since 2×123313122001499² (a number of 29 digits) contains 22 as substring.

Together with 123313122001501, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (123313122001409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61656561000749 + 61656561000750.

It is an arithmetic number, because the mean of its divisors is an integer number (61656561000750).

Almost surely, 2^{123313122001499} is an apocalyptic number.

123313122001499 is a deficient number, since it is larger than the sum of its proper divisors (1).

123313122001499 is an equidigital number, since it uses as much as digits as its factorization.

123313122001499 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 123313122001499 in words is "one hundred twenty-three trillion, three hundred thirteen billion, one hundred twenty-two million, one thousand, four hundred ninety-nine".