Base | Representation |
---|---|
bin | 11100000010011101001001… |
… | …100100110001110010001001 |
3 | 121011121201002111111020100212 |
4 | 130002131021210301302021 |
5 | 112130334123321211241 |
6 | 1114133404344210505 |
7 | 34655100610001342 |
oct | 3402351144616211 |
9 | 534551074436325 |
10 | 123314040413321 |
11 | 3632321102855a |
12 | 119b7106769a35 |
13 | 53a6605877044 |
14 | 2264607aa10c9 |
15 | e3ca33ec0beb |
hex | 702749931c89 |
123314040413321 has 2 divisors, whose sum is σ = 123314040413322. Its totient is φ = 123314040413320.
The previous prime is 123314040413303. The next prime is 123314040413341.
123314040413321 is nontrivially palindromic in base 10.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110000766015625 + 13313274397696 = 10488125^2 + 3648736^2 .
It is a palprime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123314040413321 is a prime.
It is not a weakly prime, because it can be changed into another prime (123314040413341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657020206660 + 61657020206661.
It is an arithmetic number, because the mean of its divisors is an integer number (61657020206661).
Almost surely, 2123314040413321 is an apocalyptic number.
It is an amenable number.
123314040413321 is a deficient number, since it is larger than the sum of its proper divisors (1).
123314040413321 is an equidigital number, since it uses as much as digits as its factorization.
123314040413321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 32.
The spelling of 123314040413321 in words is "one hundred twenty-three trillion, three hundred fourteen billion, forty million, four hundred thirteen thousand, three hundred twenty-one".
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