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1233142404493 is a prime number
BaseRepresentation
bin10001111100011101000…
…000111101010110001101
311100212221210222200221011
4101330131000331112031
5130200433423420433
62342255305205221
7155043263331016
oct21743500752615
94325853880834
101233142404493
11435a7781512a
1217aba8a90811
138c391a03c3c
144398204800d
15221246373cd
hex11f1d03d58d

1233142404493 has 2 divisors, whose sum is σ = 1233142404494. Its totient is φ = 1233142404492.

The previous prime is 1233142404401. The next prime is 1233142404503. The reversal of 1233142404493 is 3944042413321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1229053825129 + 4088579364 = 1108627^2 + 63942^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233142404493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1233142401493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616571202246 + 616571202247.

It is an arithmetic number, because the mean of its divisors is an integer number (616571202247).

Almost surely, 21233142404493 is an apocalyptic number.

It is an amenable number.

1233142404493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233142404493 is an equidigital number, since it uses as much as digits as its factorization.

1233142404493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 1233142404493 in words is "one trillion, two hundred thirty-three billion, one hundred forty-two million, four hundred four thousand, four hundred ninety-three".