Base | Representation |
---|---|
bin | 11100000010011101011010… |
… | …111001101100111111111101 |
3 | 121011121201211202111020012011 |
4 | 130002131122321230333331 |
5 | 112130340222231031141 |
6 | 1114133453251011221 |
7 | 34655111036616562 |
oct | 3402353271547775 |
9 | 534551752436164 |
10 | 123314331111421 |
11 | 3632335012931a |
12 | 119b7187b99b11 |
13 | 53a6650b68c58 |
14 | 2264634532869 |
15 | e3ca4e793881 |
hex | 70275ae6cffd |
123314331111421 has 2 divisors, whose sum is σ = 123314331111422. Its totient is φ = 123314331111420.
The previous prime is 123314331111397. The next prime is 123314331111451. The reversal of 123314331111421 is 124111133413321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106965134336025 + 16349196775396 = 10342395^2 + 4043414^2 .
It is an emirp because it is prime and its reverse (124111133413321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123314331111421 - 221 = 123314329014269 is a prime.
It is a super-2 number, since 2×1233143311114212 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123314331111451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657165555710 + 61657165555711.
It is an arithmetic number, because the mean of its divisors is an integer number (61657165555711).
Almost surely, 2123314331111421 is an apocalyptic number.
It is an amenable number.
123314331111421 is a deficient number, since it is larger than the sum of its proper divisors (1).
123314331111421 is an equidigital number, since it uses as much as digits as its factorization.
123314331111421 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 31.
Adding to 123314331111421 its reverse (124111133413321), we get a palindrome (247425464524742).
The spelling of 123314331111421 in words is "one hundred twenty-three trillion, three hundred fourteen billion, three hundred thirty-one million, one hundred eleven thousand, four hundred twenty-one".
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