Base | Representation |
---|---|
bin | 111001011011000011… |
… | …0111000000011101101 |
3 | 102210021222200112100122 |
4 | 1302312012320003231 |
5 | 4010021432340302 |
6 | 132352210134325 |
7 | 11623562411315 |
oct | 1626606700355 |
9 | 383258615318 |
10 | 123314340077 |
11 | 4832a803955 |
12 | 1ba958813a5 |
13 | b822a4a846 |
14 | 5d7b5b6445 |
15 | 331ae3c3a2 |
hex | 1cb61b80ed |
123314340077 has 2 divisors, whose sum is σ = 123314340078. Its totient is φ = 123314340076.
The previous prime is 123314340073. The next prime is 123314340137. The reversal of 123314340077 is 770043413321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68377543081 + 54936796996 = 261491^2 + 234386^2 .
It is a cyclic number.
It is not a de Polignac number, because 123314340077 - 22 = 123314340073 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123314340073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657170038 + 61657170039.
It is an arithmetic number, because the mean of its divisors is an integer number (61657170039).
Almost surely, 2123314340077 is an apocalyptic number.
It is an amenable number.
123314340077 is a deficient number, since it is larger than the sum of its proper divisors (1).
123314340077 is an equidigital number, since it uses as much as digits as its factorization.
123314340077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42336, while the sum is 35.
Adding to 123314340077 its reverse (770043413321), we get a palindrome (893357753398).
The spelling of 123314340077 in words is "one hundred twenty-three billion, three hundred fourteen million, three hundred forty thousand, seventy-seven".
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