Base | Representation |
---|---|
bin | 1011001101110010001011… |
… | …0000110000011011001111 |
3 | 1121122212120212012201001001 |
4 | 2303130202300300123033 |
5 | 3104014234141012143 |
6 | 42120552133401131 |
7 | 2411626303131451 |
oct | 263344260603317 |
9 | 47585525181031 |
10 | 12331434313423 |
11 | 3a24806210025 |
12 | 1471ab84991a7 |
13 | 6b5b06ab7444 |
14 | 308bb78502d1 |
15 | 165b800ca14d |
hex | b3722c306cf |
12331434313423 has 2 divisors, whose sum is σ = 12331434313424. Its totient is φ = 12331434313422.
The previous prime is 12331434313409. The next prime is 12331434313519. The reversal of 12331434313423 is 32431343413321.
12331434313423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12331434313423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12331434313223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165717156711 + 6165717156712.
It is an arithmetic number, because the mean of its divisors is an integer number (6165717156712).
Almost surely, 212331434313423 is an apocalyptic number.
12331434313423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12331434313423 is an equidigital number, since it uses as much as digits as its factorization.
12331434313423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 37.
Adding to 12331434313423 its reverse (32431343413321), we get a palindrome (44762777726744).
The spelling of 12331434313423 in words is "twelve trillion, three hundred thirty-one billion, four hundred thirty-four million, three hundred thirteen thousand, four hundred twenty-three".
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