Base | Representation |
---|---|
bin | 10001111100100000100… |
… | …001110100010111010011 |
3 | 11100220002220220110002202 |
4 | 101330200201310113103 |
5 | 130201044021200344 |
6 | 2342305212433415 |
7 | 155044610344055 |
oct | 21744041642723 |
9 | 4326086813082 |
10 | 1233201350099 |
11 | 435aa8015904 |
12 | 17b00477886b |
13 | 8c3a0ca1cb4 |
14 | 43989bcd8d5 |
15 | 221298cc94e |
hex | 11f208745d3 |
1233201350099 has 2 divisors, whose sum is σ = 1233201350100. Its totient is φ = 1233201350098.
The previous prime is 1233201350021. The next prime is 1233201350107. The reversal of 1233201350099 is 9900531023321.
It is a strong prime.
It is an emirp because it is prime and its reverse (9900531023321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1233201350099 - 28 = 1233201349843 is a prime.
It is not a weakly prime, because it can be changed into another prime (1233201350699) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616600675049 + 616600675050.
It is an arithmetic number, because the mean of its divisors is an integer number (616600675050).
Almost surely, 21233201350099 is an apocalyptic number.
1233201350099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233201350099 is an equidigital number, since it uses as much as digits as its factorization.
1233201350099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43740, while the sum is 38.
The spelling of 1233201350099 in words is "one trillion, two hundred thirty-three billion, two hundred one million, three hundred fifty thousand, ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •