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12332014201321 is a prime number
BaseRepresentation
bin1011001101110100010101…
…0100110110100111101001
31121122221002021101001200121
42303131011110312213221
53104021431113420241
642121125450403241
72411646544113643
oct263350524664751
947587067331617
1012332014201321
113a24a83581421
12147203a730521
136b5b99c90889
14308c3087d893
15165bb5e73ad1
hexb37455369e9

12332014201321 has 2 divisors, whose sum is σ = 12332014201322. Its totient is φ = 12332014201320.

The previous prime is 12332014201307. The next prime is 12332014201393. The reversal of 12332014201321 is 12310241023321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9395383605721 + 2936630595600 = 3065189^2 + 1713660^2 .

It is a cyclic number.

It is not a de Polignac number, because 12332014201321 - 29 = 12332014200809 is a prime.

It is a super-3 number, since 3×123320142013213 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12332014201301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166007100660 + 6166007100661.

It is an arithmetic number, because the mean of its divisors is an integer number (6166007100661).

Almost surely, 212332014201321 is an apocalyptic number.

It is an amenable number.

12332014201321 is a deficient number, since it is larger than the sum of its proper divisors (1).

12332014201321 is an equidigital number, since it uses as much as digits as its factorization.

12332014201321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 12332014201321 its reverse (12310241023321), we get a palindrome (24642255224642).

The spelling of 12332014201321 in words is "twelve trillion, three hundred thirty-two billion, fourteen million, two hundred one thousand, three hundred twenty-one".