Base | Representation |
---|---|
bin | 1011001101110100101010… |
… | …0100111101110010111111 |
3 | 1121122221022102011111120212 |
4 | 2303131022210331302333 |
5 | 3104022121142423403 |
6 | 42121142315103035 |
7 | 2411651664044531 |
oct | 263351244756277 |
9 | 47587272144525 |
10 | 12332102311103 |
11 | 3a25019291623 |
12 | 1472064141a7b |
13 | 6b5bb2300343 |
14 | 308c3c457851 |
15 | 165bbda7a4d8 |
hex | b374a93dcbf |
12332102311103 has 2 divisors, whose sum is σ = 12332102311104. Its totient is φ = 12332102311102.
The previous prime is 12332102311097. The next prime is 12332102311223. The reversal of 12332102311103 is 30111320123321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12332102311103 - 210 = 12332102310079 is a prime.
It is a super-3 number, since 3×123321023111033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12332102311603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166051155551 + 6166051155552.
It is an arithmetic number, because the mean of its divisors is an integer number (6166051155552).
Almost surely, 212332102311103 is an apocalyptic number.
12332102311103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12332102311103 is an equidigital number, since it uses as much as digits as its factorization.
12332102311103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12332102311103 its reverse (30111320123321), we get a palindrome (42443422434424).
The spelling of 12332102311103 in words is "twelve trillion, three hundred thirty-two billion, one hundred two million, three hundred eleven thousand, one hundred three".
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