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12332133130000 = 245429233182509
BaseRepresentation
bin1011001101110100110001…
…1010100001111100010000
31121122221101120011021011111
42303131030122201330100
53104022202040130000
642121145335423104
72411652520023535
oct263351432417420
947587346137144
1012332133130000
113a25034721292
121472072524a94
136b5bb8800c88
14308c4259ad8c
15165bc1616cba
hexb374c6a1f10

12332133130000 has 200 divisors, whose sum is σ = 31019622262200. Its totient is φ = 4742287872000.

The previous prime is 12332133129991. The next prime is 12332133130073. The reversal of 12332133130000 is 3133123321.

It can be written as a sum of positive squares in 20 ways, for example, as 11884925292304 + 447207837696 = 3447452^2 + 668736^2 .

It is a tau number, because it is divible by the number of its divisors (200).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 67478746 + ... + 67661254.

It is an arithmetic number, because the mean of its divisors is an integer number (155098111311).

Almost surely, 212332133130000 is an apocalyptic number.

12332133130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12332133130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15509811131100).

12332133130000 is an abundant number, since it is smaller than the sum of its proper divisors (18687489132200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12332133130000 is a wasteful number, since it uses less digits than its factorization.

12332133130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182799 (or 182778 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 12332133130000 its reverse (3133123321), we get a palindrome (12335266253321).

The spelling of 12332133130000 in words is "twelve trillion, three hundred thirty-two billion, one hundred thirty-three million, one hundred thirty thousand".