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123321342311131 is a prime number
BaseRepresentation
bin11100000010100011111100…
…110011010011101011011011
3121011122101221101022002002111
4130002203330303103223123
5112130444102112424011
61114141013105213151
734655446553053216
oct3402437463235333
9534571841262074
10123321342311131
1136326318832448
12119b86040311b7
1353a71ca593833
142264adb76677d
15e3cd10071121
hex7028fccd3adb

123321342311131 has 2 divisors, whose sum is σ = 123321342311132. Its totient is φ = 123321342311130.

The previous prime is 123321342311077. The next prime is 123321342311177. The reversal of 123321342311131 is 131113243123321.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123321342311131 - 235 = 123286982572763 is a prime.

It is a super-2 number, since 2×1233213423111312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123321342311093 and 123321342311102.

It is not a weakly prime, because it can be changed into another prime (123321342381131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61660671155565 + 61660671155566.

It is an arithmetic number, because the mean of its divisors is an integer number (61660671155566).

Almost surely, 2123321342311131 is an apocalyptic number.

123321342311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

123321342311131 is an equidigital number, since it uses as much as digits as its factorization.

123321342311131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776, while the sum is 31.

Adding to 123321342311131 its reverse (131113243123321), we get a palindrome (254434585434452).

The spelling of 123321342311131 in words is "one hundred twenty-three trillion, three hundred twenty-one billion, three hundred forty-two million, three hundred eleven thousand, one hundred thirty-one".