Base | Representation |
---|---|
bin | 11100000010100101101011… |
… | …100011000001001011000011 |
3 | 121011122120201212110022010121 |
4 | 130002211223203001023003 |
5 | 112131011403234441003 |
6 | 1114141521320441111 |
7 | 34655543603600326 |
oct | 3402455343011303 |
9 | 534576655408117 |
10 | 123323200312003 |
11 | 36327091601a5a |
12 | 119b8a42319197 |
13 | 53a74354b0933 |
14 | 2264c3641a7bd |
15 | e3cdbd234cbd |
hex | 70296b8c12c3 |
123323200312003 has 2 divisors, whose sum is σ = 123323200312004. Its totient is φ = 123323200312002.
The previous prime is 123323200311989. The next prime is 123323200312061. The reversal of 123323200312003 is 300213002323321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123323200312003 is a prime.
It is a super-2 number, since 2×1233232003120032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (123323200312303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61661600156001 + 61661600156002.
It is an arithmetic number, because the mean of its divisors is an integer number (61661600156002).
Almost surely, 2123323200312003 is an apocalyptic number.
123323200312003 is a deficient number, since it is larger than the sum of its proper divisors (1).
123323200312003 is an equidigital number, since it uses as much as digits as its factorization.
123323200312003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 123323200312003 its reverse (300213002323321), we get a palindrome (423536202635324).
The spelling of 123323200312003 in words is "one hundred twenty-three trillion, three hundred twenty-three billion, two hundred million, three hundred twelve thousand, three".
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