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123325804741 is a prime number
BaseRepresentation
bin111001011011011001…
…0100111000011000101
3102210022210020222220211
41302312302213003011
54010032401222431
6132353255555421
711624062021066
oct1626662470305
9383283228824
10123325804741
1148336224487
121ba9968bb71
13b825232c79
145d7cd1c56d
15331be542b1
hex1cb6ca70c5

123325804741 has 2 divisors, whose sum is σ = 123325804742. Its totient is φ = 123325804740.

The previous prime is 123325804699. The next prime is 123325804747. The reversal of 123325804741 is 147408523321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122958929025 + 366875716 = 350655^2 + 19154^2 .

It is an emirp because it is prime and its reverse (147408523321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123325804741 - 235 = 88966066373 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123325804694 and 123325804703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123325804747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61662902370 + 61662902371.

It is an arithmetic number, because the mean of its divisors is an integer number (61662902371).

Almost surely, 2123325804741 is an apocalyptic number.

It is an amenable number.

123325804741 is a deficient number, since it is larger than the sum of its proper divisors (1).

123325804741 is an equidigital number, since it uses as much as digits as its factorization.

123325804741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 40.

The spelling of 123325804741 in words is "one hundred twenty-three billion, three hundred twenty-five million, eight hundred four thousand, seven hundred forty-one".