Base | Representation |
---|---|
bin | 1011001101111000110101… |
… | …1000100011010000100011 |
3 | 1121200001012112012000021022 |
4 | 2303132031120203100203 |
5 | 3104031420110131042 |
6 | 42121445434120055 |
7 | 2412021523620533 |
oct | 263361530432043 |
9 | 47601175160238 |
10 | 12333223130147 |
11 | 3a25543a26557 |
12 | 147231758002b |
13 | 6b603059018a |
14 | 308d072554c3 |
15 | 165c37174cd2 |
hex | b378d623423 |
12333223130147 has 2 divisors, whose sum is σ = 12333223130148. Its totient is φ = 12333223130146.
The previous prime is 12333223129967. The next prime is 12333223130149. The reversal of 12333223130147 is 74103132233321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12333223130147 is a prime.
Together with 12333223130149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12333223130149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166611565073 + 6166611565074.
It is an arithmetic number, because the mean of its divisors is an integer number (6166611565074).
Almost surely, 212333223130147 is an apocalyptic number.
12333223130147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12333223130147 is an equidigital number, since it uses as much as digits as its factorization.
12333223130147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 12333223130147 its reverse (74103132233321), we get a palindrome (86436355363468).
The spelling of 12333223130147 in words is "twelve trillion, three hundred thirty-three billion, two hundred twenty-three million, one hundred thirty thousand, one hundred forty-seven".
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