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12333223130147 is a prime number
BaseRepresentation
bin1011001101111000110101…
…1000100011010000100011
31121200001012112012000021022
42303132031120203100203
53104031420110131042
642121445434120055
72412021523620533
oct263361530432043
947601175160238
1012333223130147
113a25543a26557
12147231758002b
136b603059018a
14308d072554c3
15165c37174cd2
hexb378d623423

12333223130147 has 2 divisors, whose sum is σ = 12333223130148. Its totient is φ = 12333223130146.

The previous prime is 12333223129967. The next prime is 12333223130149. The reversal of 12333223130147 is 74103132233321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12333223130147 is a prime.

Together with 12333223130149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12333223130149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166611565073 + 6166611565074.

It is an arithmetic number, because the mean of its divisors is an integer number (6166611565074).

Almost surely, 212333223130147 is an apocalyptic number.

12333223130147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12333223130147 is an equidigital number, since it uses as much as digits as its factorization.

12333223130147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 35.

Adding to 12333223130147 its reverse (74103132233321), we get a palindrome (86436355363468).

The spelling of 12333223130147 in words is "twelve trillion, three hundred thirty-three billion, two hundred twenty-three million, one hundred thirty thousand, one hundred forty-seven".