Base | Representation |
---|---|
bin | 111001011011101001… |
… | …0000101010001101111 |
3 | 102210100100210011011211 |
4 | 1302313102011101233 |
5 | 4010042004230043 |
6 | 132354152455251 |
7 | 11624222112304 |
oct | 1626722052157 |
9 | 383310704154 |
10 | 123334055023 |
11 | 4833a949aa3 |
12 | 1baa03aa527 |
13 | b826b612aa |
14 | 5d800690ab |
15 | 331ca33a9d |
hex | 1cb748546f |
123334055023 has 2 divisors, whose sum is σ = 123334055024. Its totient is φ = 123334055022.
The previous prime is 123334054981. The next prime is 123334055041. The reversal of 123334055023 is 320550433321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123334055023 is a prime.
It is a super-2 number, since 2×1233340550232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123334055063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61667027511 + 61667027512.
It is an arithmetic number, because the mean of its divisors is an integer number (61667027512).
Almost surely, 2123334055023 is an apocalyptic number.
123334055023 is a deficient number, since it is larger than the sum of its proper divisors (1).
123334055023 is an equidigital number, since it uses as much as digits as its factorization.
123334055023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 123334055023 its reverse (320550433321), we get a palindrome (443884488344).
The spelling of 123334055023 in words is "one hundred twenty-three billion, three hundred thirty-four million, fifty-five thousand, twenty-three".
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