Base | Representation |
---|---|
bin | 1011001101111011110000… |
… | …1111101110110001001111 |
3 | 1121200010020022120222020121 |
4 | 2303132330033232301033 |
5 | 3104040022343102101 |
6 | 42122055441325411 |
7 | 2412050151430432 |
oct | 263367417566117 |
9 | 47603208528217 |
10 | 12334009347151 |
11 | 3a25907802a78 |
12 | 14724b6936867 |
13 | 6b612742863b |
14 | 308d7d833819 |
15 | 165c811c80a1 |
hex | b37bc3eec4f |
12334009347151 has 2 divisors, whose sum is σ = 12334009347152. Its totient is φ = 12334009347150.
The previous prime is 12334009347131. The next prime is 12334009347161. The reversal of 12334009347151 is 15174390043321.
It is a strong prime.
It is an emirp because it is prime and its reverse (15174390043321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12334009347151 - 25 = 12334009347119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12334009347098 and 12334009347107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12334009347131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6167004673575 + 6167004673576.
It is an arithmetic number, because the mean of its divisors is an integer number (6167004673576).
Almost surely, 212334009347151 is an apocalyptic number.
12334009347151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12334009347151 is an equidigital number, since it uses as much as digits as its factorization.
12334009347151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 43.
The spelling of 12334009347151 in words is "twelve trillion, three hundred thirty-four billion, nine million, three hundred forty-seven thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •