Base | Representation |
---|---|
bin | 10001111100101101001… |
… | …101111011101111100101 |
3 | 11100220122202111102212022 |
4 | 101330231031323233211 |
5 | 130202013021210003 |
6 | 2342342255432525 |
7 | 155053104032015 |
oct | 21745515735745 |
9 | 4326582442768 |
10 | 1233414241253 |
11 | 4360a7203107 |
12 | 17b063b25745 |
13 | 8c406120aac |
14 | 439aa1a9c45 |
15 | 2213d431738 |
hex | 11f2d37bbe5 |
1233414241253 has 2 divisors, whose sum is σ = 1233414241254. Its totient is φ = 1233414241252.
The previous prime is 1233414241237. The next prime is 1233414241271. The reversal of 1233414241253 is 3521424143321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 893219680609 + 340194560644 = 945103^2 + 583262^2 .
It is a cyclic number.
It is not a de Polignac number, because 1233414241253 - 24 = 1233414241237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1233414241273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616707120626 + 616707120627.
It is an arithmetic number, because the mean of its divisors is an integer number (616707120627).
Almost surely, 21233414241253 is an apocalyptic number.
It is an amenable number.
1233414241253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233414241253 is an equidigital number, since it uses as much as digits as its factorization.
1233414241253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 35.
Adding to 1233414241253 its reverse (3521424143321), we get a palindrome (4754838384574).
The spelling of 1233414241253 in words is "one trillion, two hundred thirty-three billion, four hundred fourteen million, two hundred forty-one thousand, two hundred fifty-three".
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