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1233423053153 is a prime number
BaseRepresentation
bin10001111100101101101…
…111100011000101100001
311100220200101002010111222
4101330231233203011201
5130202022300200103
62342343212344425
7155053241652464
oct21745557430541
94326611063458
101233423053153
11436101181675
1217b066a75115
138c407bb7935
14439ab4212db
152213e0c2638
hex11f2dbe3161

1233423053153 has 2 divisors, whose sum is σ = 1233423053154. Its totient is φ = 1233423053152.

The previous prime is 1233423053117. The next prime is 1233423053171. The reversal of 1233423053153 is 3513503243321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1091224676689 + 142198376464 = 1044617^2 + 377092^2 .

It is a cyclic number.

It is not a de Polignac number, because 1233423053153 - 218 = 1233422791009 is a prime.

It is not a weakly prime, because it can be changed into another prime (1233423053353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616711526576 + 616711526577.

It is an arithmetic number, because the mean of its divisors is an integer number (616711526577).

Almost surely, 21233423053153 is an apocalyptic number.

It is an amenable number.

1233423053153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233423053153 is an equidigital number, since it uses as much as digits as its factorization.

1233423053153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 1233423053153 its reverse (3513503243321), we get a palindrome (4746926296474).

The spelling of 1233423053153 in words is "one trillion, two hundred thirty-three billion, four hundred twenty-three million, fifty-three thousand, one hundred fifty-three".