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1233423053117 is a prime number
BaseRepresentation
bin10001111100101101101…
…111100011000100111101
311100220200101002010110122
4101330231233203010331
5130202022300144432
62342343212344325
7155053241652413
oct21745557430475
94326611063418
101233423053117
11436101181642
1217b066a750a5
138c407bb7908
14439ab4212b3
152213e0c2612
hex11f2dbe313d

1233423053117 has 2 divisors, whose sum is σ = 1233423053118. Its totient is φ = 1233423053116.

The previous prime is 1233423053047. The next prime is 1233423053153. The reversal of 1233423053117 is 7113503243321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1084126593796 + 149296459321 = 1041214^2 + 386389^2 .

It is an emirp because it is prime and its reverse (7113503243321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233423053117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1233423058117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616711526558 + 616711526559.

It is an arithmetic number, because the mean of its divisors is an integer number (616711526559).

Almost surely, 21233423053117 is an apocalyptic number.

It is an amenable number.

1233423053117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233423053117 is an equidigital number, since it uses as much as digits as its factorization.

1233423053117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45360, while the sum is 35.

Adding to 1233423053117 its reverse (7113503243321), we get a palindrome (8346926296438).

The spelling of 1233423053117 in words is "one trillion, two hundred thirty-three billion, four hundred twenty-three million, fifty-three thousand, one hundred seventeen".