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123345352340503 is a prime number
BaseRepresentation
bin11100000010111010010011…
…111010010011010000010111
3121011201200220200101221111121
4130002322103322103100113
5112131342240144344003
61114200023403344411
734660256546664646
oct3402722372232027
9534650820357447
10123345352340503
1136335519875927
1211a011a4b22107
1353a9555991bc7
142265d3845335d
15e3d767d93cbd
hex702e93e93417

123345352340503 has 2 divisors, whose sum is σ = 123345352340504. Its totient is φ = 123345352340502.

The previous prime is 123345352340479. The next prime is 123345352340603. The reversal of 123345352340503 is 305043253543321.

It is a weak prime.

It is an emirp because it is prime and its reverse (305043253543321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123345352340503 - 29 = 123345352339991 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 123345352340503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123345352340603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61672676170251 + 61672676170252.

It is an arithmetic number, because the mean of its divisors is an integer number (61672676170252).

Almost surely, 2123345352340503 is an apocalyptic number.

123345352340503 is a deficient number, since it is larger than the sum of its proper divisors (1).

123345352340503 is an equidigital number, since it uses as much as digits as its factorization.

123345352340503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944000, while the sum is 43.

The spelling of 123345352340503 in words is "one hundred twenty-three trillion, three hundred forty-five billion, three hundred fifty-two million, three hundred forty thousand, five hundred three".