123345510254441 has 2 divisors, whose sum is σ = 123345510254442. Its totient is φ = 123345510254440.

The previous prime is 123345510254411. The next prime is 123345510254443. The reversal of 123345510254441 is 144452015543321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113655961512025 + 9689548742416 = 10660955^2 + 3112804^2 .

It is a cyclic number.

It is not a de Polignac number, because 123345510254441 - 2⁶ = 123345510254377 is a prime.

It is a super-2 number, since 2×123345510254441² (a number of 29 digits) contains 22 as substring.

Together with 123345510254443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 123345510254392 and 123345510254401.

It is not a weakly prime, because it can be changed into another prime (123345510254443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61672755127220 + 61672755127221.

It is an arithmetic number, because the mean of its divisors is an integer number (61672755127221).

Almost surely, 2^{123345510254441} is an apocalyptic number.

It is an amenable number.

123345510254441 is a deficient number, since it is larger than the sum of its proper divisors (1).

123345510254441 is an equidigital number, since it uses as much as digits as its factorization.

123345510254441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152000, while the sum is 44.

Adding to 123345510254441 its reverse (144452015543321), we get a palindrome (267797525797762).

The spelling of 123345510254441 in words is "one hundred twenty-three trillion, three hundred forty-five billion, five hundred ten million, two hundred fifty-four thousand, four hundred forty-one".