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1233536135053 is a prime number
BaseRepresentation
bin10001111100110100011…
…110111010111110001101
311100220222020212021201111
4101330310132322332031
5130202240222310203
62342402332212021
7155056114101355
oct21746436727615
94326866767644
101233536135053
11436159a98792
1217b09890a011
138c42545b9c1
14439bc459b65
1522148ead26d
hex11f347baf8d

1233536135053 has 2 divisors, whose sum is σ = 1233536135054. Its totient is φ = 1233536135052.

The previous prime is 1233536135017. The next prime is 1233536135087. The reversal of 1233536135053 is 3505316353321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1024008396489 + 209527738564 = 1011933^2 + 457742^2 .

It is a cyclic number.

It is not a de Polignac number, because 1233536135053 - 233 = 1224946200461 is a prime.

It is a super-2 number, since 2×12335361350532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1233536134997 and 1233536135015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1233536130053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616768067526 + 616768067527.

It is an arithmetic number, because the mean of its divisors is an integer number (616768067527).

Almost surely, 21233536135053 is an apocalyptic number.

It is an amenable number.

1233536135053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233536135053 is an equidigital number, since it uses as much as digits as its factorization.

1233536135053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 364500, while the sum is 40.

The spelling of 1233536135053 in words is "one trillion, two hundred thirty-three billion, five hundred thirty-six million, one hundred thirty-five thousand, fifty-three".