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1233909815053 is a prime number
BaseRepresentation
bin10001111101001010110…
…000011001011100001101
311100221221022000012022111
4101331022300121130031
5130204021403040203
62342503401344021
7155101302242416
oct21751260313415
94327838005274
101233909815053
11436330a17033
1217b181a98011
138c4849b6326
1443a15d2c80d
152216bbc326d
hex11f4ac1970d

1233909815053 has 2 divisors, whose sum is σ = 1233909815054. Its totient is φ = 1233909815052.

The previous prime is 1233909815027. The next prime is 1233909815059. The reversal of 1233909815053 is 3505189093321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1021437678244 + 212472136809 = 1010662^2 + 460947^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233909815053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1233909814988 and 1233909815006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1233909815059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616954907526 + 616954907527.

It is an arithmetic number, because the mean of its divisors is an integer number (616954907527).

Almost surely, 21233909815053 is an apocalyptic number.

It is an amenable number.

1233909815053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233909815053 is an equidigital number, since it uses as much as digits as its factorization.

1233909815053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 874800, while the sum is 49.

The spelling of 1233909815053 in words is "one trillion, two hundred thirty-three billion, nine hundred nine million, eight hundred fifteen thousand, fifty-three".