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12340578739141 is a prime number
BaseRepresentation
bin1011001110010100001111…
…0011111110001111000101
31121200202012011001122220001
42303211003303332033011
53104142001124123031
642125103354241301
72412402021354652
oct263450363761705
947622164048801
1012340578739141
113a28678a86454
12147382aa26231
136b6933464333
143094040dcc29
15166017cd4861
hexb3943cfe3c5

12340578739141 has 2 divisors, whose sum is σ = 12340578739142. Its totient is φ = 12340578739140.

The previous prime is 12340578739133. The next prime is 12340578739163. The reversal of 12340578739141 is 14193787504321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11671583976900 + 668994762241 = 3416370^2 + 817921^2 .

It is a cyclic number.

It is not a de Polignac number, because 12340578739141 - 23 = 12340578739133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12340578731141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6170289369570 + 6170289369571.

It is an arithmetic number, because the mean of its divisors is an integer number (6170289369571).

Almost surely, 212340578739141 is an apocalyptic number.

It is an amenable number.

12340578739141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12340578739141 is an equidigital number, since it uses as much as digits as its factorization.

12340578739141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5080320, while the sum is 55.

The spelling of 12340578739141 in words is "twelve trillion, three hundred forty billion, five hundred seventy-eight million, seven hundred thirty-nine thousand, one hundred forty-one".