Base | Representation |
---|---|
bin | 11100000011110111101111… |
… | …111101111010010010011000 |
3 | 121011222000012011122022112020 |
4 | 130003313233331322102120 |
5 | 112133432341223100440 |
6 | 1114250213415214440 |
7 | 34665113405620200 |
oct | 3403675775722230 |
9 | 534860164568466 |
10 | 123411321300120 |
11 | 363604a1602667 |
12 | 11a11b35977420 |
13 | 53b2839c3a459 |
14 | 22691d5955400 |
15 | e4032964c3d0 |
hex | 703deff7a498 |
123411321300120 has 384 divisors, whose sum is σ = 445537909555200. Its totient is φ = 27239122713600.
The previous prime is 123411321300119. The next prime is 123411321300193. The reversal of 123411321300120 is 21003123114321.
It is a super-2 number, since 2×1234113213001202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 83296761 + ... + 84765399.
It is an arithmetic number, because the mean of its divisors is an integer number (1160254972800).
Almost surely, 2123411321300120 is an apocalyptic number.
123411321300120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 123411321300120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222768954777600).
123411321300120 is an abundant number, since it is smaller than the sum of its proper divisors (322126588255080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123411321300120 is a wasteful number, since it uses less digits than its factorization.
123411321300120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1469159 (or 1469148 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 123411321300120 its reverse (21003123114321), we get a palindrome (144414444414441).
The spelling of 123411321300120 in words is "one hundred twenty-three trillion, four hundred eleven billion, three hundred twenty-one million, three hundred thousand, one hundred twenty".
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