Base | Representation |
---|---|
bin | 1011001110010110111101… |
… | …1110100001100110010001 |
3 | 1121200211002012112100010010 |
4 | 2303211233132201212101 |
5 | 3104200001144024241 |
6 | 42125304204025133 |
7 | 2412426125221443 |
oct | 263455736414621 |
9 | 47624065470103 |
10 | 12341311314321 |
11 | 3a28a14554a90 |
12 | 14739b42321a9 |
13 | 6b6a1c16a882 |
14 | 309473516493 |
15 | 16605c28dd16 |
hex | b396f7a1991 |
12341311314321 has 32 divisors (see below), whose sum is σ = 18540599869440. Its totient is φ = 7234189689600.
The previous prime is 12341311314313. The next prime is 12341311314347.
It is a happy number.
12341311314321 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 12341311314321 - 23 = 12341311314313 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12341311314361) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1629720 + ... + 5228633.
It is an arithmetic number, because the mean of its divisors is an integer number (579393745920).
Almost surely, 212341311314321 is an apocalyptic number.
12341311314321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
12341311314321 is a deficient number, since it is larger than the sum of its proper divisors (6199288555119).
12341311314321 is a wasteful number, since it uses less digits than its factorization.
12341311314321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6860157.
The product of its digits is 5184, while the sum is 30.
It can be divided in two parts, 1234131 and 1314321, that added together give a palindrome (2548452).
The spelling of 12341311314321 in words is "twelve trillion, three hundred forty-one billion, three hundred eleven million, three hundred fourteen thousand, three hundred twenty-one".
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