Base | Representation |
---|---|
bin | 10110111111001101… |
… | …10000000100000111 |
3 | 1011212002112200201011 |
4 | 23133212300010013 |
5 | 200233400141403 |
6 | 5400343143051 |
7 | 614555162206 |
oct | 133746600407 |
9 | 34762480634 |
10 | 12341412103 |
11 | 5263450639 |
12 | 2485144a87 |
13 | 1218b01b17 |
14 | 8510d123d |
15 | 4c370ea6d |
hex | 2df9b0107 |
12341412103 has 2 divisors, whose sum is σ = 12341412104. Its totient is φ = 12341412102.
The previous prime is 12341412073. The next prime is 12341412113. The reversal of 12341412103 is 30121414321.
12341412103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12341412103 - 229 = 11804541191 is a prime.
It is an alternating number because its digits alternate between odd and even.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12341412113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6170706051 + 6170706052.
It is an arithmetic number, because the mean of its divisors is an integer number (6170706052).
Almost surely, 212341412103 is an apocalyptic number.
12341412103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12341412103 is an equidigital number, since it uses as much as digits as its factorization.
12341412103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 12341412103 its reverse (30121414321), we get a palindrome (42462826424).
The spelling of 12341412103 in words is "twelve billion, three hundred forty-one million, four hundred twelve thousand, one hundred three".
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