Base | Representation |
---|---|
bin | 111001011110001111… |
… | …0111111011101011011 |
3 | 102210120102222221021122 |
4 | 1302330132333131123 |
5 | 4010231324401042 |
6 | 132410551155455 |
7 | 11626331645201 |
oct | 1627436773533 |
9 | 383512887248 |
10 | 123421325147 |
11 | 4838513636a |
12 | 1bb05675b8b |
13 | b83bc68813 |
14 | 5d8b8a5071 |
15 | 33255217d2 |
hex | 1cbc7bf75b |
123421325147 has 2 divisors, whose sum is σ = 123421325148. Its totient is φ = 123421325146.
The previous prime is 123421325107. The next prime is 123421325171. The reversal of 123421325147 is 741523124321.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123421325147 - 210 = 123421324123 is a prime.
It is not a weakly prime, because it can be changed into another prime (123421325107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61710662573 + 61710662574.
It is an arithmetic number, because the mean of its divisors is an integer number (61710662574).
Almost surely, 2123421325147 is an apocalyptic number.
123421325147 is a deficient number, since it is larger than the sum of its proper divisors (1).
123421325147 is an equidigital number, since it uses as much as digits as its factorization.
123421325147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40320, while the sum is 35.
Adding to 123421325147 its reverse (741523124321), we get a palindrome (864944449468).
The spelling of 123421325147 in words is "one hundred twenty-three billion, four hundred twenty-one million, three hundred twenty-five thousand, one hundred forty-seven".
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