Base | Representation |
---|---|
bin | 1011001110011101101101… |
… | …1110011111000000101011 |
3 | 1121200222202110222212001121 |
4 | 2303213123132133000223 |
5 | 3104212204022234201 |
6 | 42130204052000111 |
7 | 2412522046320466 |
oct | 263473336370053 |
9 | 47628673885047 |
10 | 12343123243051 |
11 | 3a29764316947 |
12 | 147421b000037 |
13 | 6b6c4a676353 |
14 | 3095a60162dd |
15 | 1661163a19a1 |
hex | b39db79f02b |
12343123243051 has 2 divisors, whose sum is σ = 12343123243052. Its totient is φ = 12343123243050.
The previous prime is 12343123243027. The next prime is 12343123243163. The reversal of 12343123243051 is 15034232134321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12343123243051 - 221 = 12343121145899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12343123242998 and 12343123243016.
It is not a weakly prime, because it can be changed into another prime (12343123243651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6171561621525 + 6171561621526.
It is an arithmetic number, because the mean of its divisors is an integer number (6171561621526).
Almost surely, 212343123243051 is an apocalyptic number.
12343123243051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12343123243051 is an equidigital number, since it uses as much as digits as its factorization.
12343123243051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 12343123243051 its reverse (15034232134321), we get a palindrome (27377355377372).
The spelling of 12343123243051 in words is "twelve trillion, three hundred forty-three billion, one hundred twenty-three million, two hundred forty-three thousand, fifty-one".
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