Base | Representation |
---|---|
bin | 10001111101100011110… |
… | …100111110000100010001 |
3 | 11101000000121111100211012 |
4 | 101331203310332010101 |
5 | 130210402043202144 |
6 | 2343013225100305 |
7 | 155114600443133 |
oct | 21754364760421 |
9 | 4330017440735 |
10 | 1234330444049 |
11 | 4365273a18aa |
12 | 17b27a927695 |
13 | 8c520b9b421 |
14 | 43a55b43053 |
15 | 22193aade9e |
hex | 11f63d3e111 |
1234330444049 has 2 divisors, whose sum is σ = 1234330444050. Its totient is φ = 1234330444048.
The previous prime is 1234330443947. The next prime is 1234330444091. The reversal of 1234330444049 is 9404440334321.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 841151282449 + 393179161600 = 917143^2 + 627040^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1234330444049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1234330443997 and 1234330444015.
It is not a weakly prime, because it can be changed into another prime (1234330414049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617165222024 + 617165222025.
It is an arithmetic number, because the mean of its divisors is an integer number (617165222025).
Almost surely, 21234330444049 is an apocalyptic number.
It is an amenable number.
1234330444049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1234330444049 is an equidigital number, since it uses as much as digits as its factorization.
1234330444049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 41.
The spelling of 1234330444049 in words is "one trillion, two hundred thirty-four billion, three hundred thirty million, four hundred forty-four thousand, forty-nine".
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