Base | Representation |
---|---|
bin | 1011001110011110110000… |
… | …1101100111010001110111 |
3 | 1121201000111001100110122122 |
4 | 2303213230031213101313 |
5 | 3104213242413030033 |
6 | 42130252002150155 |
7 | 2412532026101501 |
oct | 263475415472167 |
9 | 47630431313578 |
10 | 12343404033143 |
11 | 3a2989886a677 |
12 | 147429905235b |
13 | 6b6c938a9531 |
14 | 3095d1428d71 |
15 | 166130d68a98 |
hex | b39ec367477 |
12343404033143 has 2 divisors, whose sum is σ = 12343404033144. Its totient is φ = 12343404033142.
The previous prime is 12343404033139. The next prime is 12343404033151. The reversal of 12343404033143 is 34133040434321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12343404033143 - 22 = 12343404033139 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12343404033193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6171702016571 + 6171702016572.
It is an arithmetic number, because the mean of its divisors is an integer number (6171702016572).
Almost surely, 212343404033143 is an apocalyptic number.
12343404033143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12343404033143 is an equidigital number, since it uses as much as digits as its factorization.
12343404033143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 12343404033143 its reverse (34133040434321), we get a palindrome (46476444467464).
The spelling of 12343404033143 in words is "twelve trillion, three hundred forty-three billion, four hundred four million, thirty-three thousand, one hundred forty-three".
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