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12344143433 is a prime number
BaseRepresentation
bin10110111111100010…
…01010111001001001
31011212021200110101112
423133301022321021
5200240100042213
65400521500105
7614620326236
oct133761127111
934767613345
1012344143433
115264a46736
122486041635
13121954a0ab
1485160278d
154c3a9dea8
hex2dfc4ae49

12344143433 has 2 divisors, whose sum is σ = 12344143434. Its totient is φ = 12344143432.

The previous prime is 12344143417. The next prime is 12344143439. The reversal of 12344143433 is 33434144321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10631259664 + 1712883769 = 103108^2 + 41387^2 .

It is a cyclic number.

It is not a de Polignac number, because 12344143433 - 24 = 12344143417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12344143433.

It is not a weakly prime, because it can be changed into another prime (12344143439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6172071716 + 6172071717.

It is an arithmetic number, because the mean of its divisors is an integer number (6172071717).

Almost surely, 212344143433 is an apocalyptic number.

It is an amenable number.

12344143433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12344143433 is an equidigital number, since it uses as much as digits as its factorization.

12344143433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 32.

Adding to 12344143433 its reverse (33434144321), we get a palindrome (45778287754).

The spelling of 12344143433 in words is "twelve billion, three hundred forty-four million, one hundred forty-three thousand, four hundred thirty-three".