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12347108981173 is a prime number
BaseRepresentation
bin1011001110101100100100…
…0010110111100110110101
31121201101001020212022220001
42303223021002313212311
53104243334344344143
642132103352111301
72413022604454321
oct263531102674665
947641036768801
1012347108981173
113a3041a14999a
121474b51995531
136b7434343385
143098634d6981
1516629b25b14d
hexb3ac90b79b5

12347108981173 has 2 divisors, whose sum is σ = 12347108981174. Its totient is φ = 12347108981172.

The previous prime is 12347108981153. The next prime is 12347108981177. The reversal of 12347108981173 is 37118980174321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11123072106129 + 1224036875044 = 3335127^2 + 1106362^2 .

It is a cyclic number.

It is not a de Polignac number, because 12347108981173 - 217 = 12347108850101 is a prime.

It is a super-2 number, since 2×123471089811732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12347108981177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6173554490586 + 6173554490587.

It is an arithmetic number, because the mean of its divisors is an integer number (6173554490587).

Almost surely, 212347108981173 is an apocalyptic number.

It is an amenable number.

12347108981173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12347108981173 is an equidigital number, since it uses as much as digits as its factorization.

12347108981173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2032128, while the sum is 55.

The spelling of 12347108981173 in words is "twelve trillion, three hundred forty-seven billion, one hundred eight million, nine hundred eighty-one thousand, one hundred seventy-three".