Base | Representation |
---|---|
bin | 111001100000100110… |
… | …0010011110110101111 |
3 | 102210202221121222122212 |
4 | 1303001030103312233 |
5 | 4010412040022111 |
6 | 132422452201035 |
7 | 11631311230403 |
oct | 1630114236657 |
9 | 383687558585 |
10 | 123500314031 |
11 | 48415786936 |
12 | 1bb2800917b |
13 | b8524338c3 |
14 | 5d98187103 |
15 | 332c42598b |
hex | 1cc1313daf |
123500314031 has 2 divisors, whose sum is σ = 123500314032. Its totient is φ = 123500314030.
The previous prime is 123500314027. The next prime is 123500314039. The reversal of 123500314031 is 130413005321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123500314031 - 22 = 123500314027 is a prime.
It is a super-2 number, since 2×1235003140312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123500313988 and 123500314006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123500314039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61750157015 + 61750157016.
It is an arithmetic number, because the mean of its divisors is an integer number (61750157016).
Almost surely, 2123500314031 is an apocalyptic number.
123500314031 is a deficient number, since it is larger than the sum of its proper divisors (1).
123500314031 is an equidigital number, since it uses as much as digits as its factorization.
123500314031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 123500314031 its reverse (130413005321), we get a palindrome (253913319352).
The spelling of 123500314031 in words is "one hundred twenty-three billion, five hundred million, three hundred fourteen thousand, thirty-one".
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