Base | Representation |
---|---|
bin | 10001111110010100111… |
… | …010110010111111110001 |
3 | 11101002011000021010212011 |
4 | 101332110322302333301 |
5 | 130214043414231103 |
6 | 2343231050002521 |
7 | 155144161145524 |
oct | 21762472627761 |
9 | 4332130233764 |
10 | 1235154055153 |
11 | 43690a29a037 |
12 | 17b46a716441 |
13 | 8c6226ca285 |
14 | 43ad3296bbb |
15 | 221e104bd6d |
hex | 11f94eb2ff1 |
1235154055153 has 2 divisors, whose sum is σ = 1235154055154. Its totient is φ = 1235154055152.
The previous prime is 1235154055141. The next prime is 1235154055193. The reversal of 1235154055153 is 3515504515321.
It is an a-pointer prime, because the next prime (1235154055193) can be obtained adding 1235154055153 to its sum of digits (40).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 980313851664 + 254840203489 = 990108^2 + 504817^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1235154055153 is a prime.
It is not a weakly prime, because it can be changed into another prime (1235154055123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617577027576 + 617577027577.
It is an arithmetic number, because the mean of its divisors is an integer number (617577027577).
Almost surely, 21235154055153 is an apocalyptic number.
It is an amenable number.
1235154055153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1235154055153 is an equidigital number, since it uses as much as digits as its factorization.
1235154055153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 225000, while the sum is 40.
The spelling of 1235154055153 in words is "one trillion, two hundred thirty-five billion, one hundred fifty-four million, fifty-five thousand, one hundred fifty-three".
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