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123525031214041 is a prime number
BaseRepresentation
bin11100000101100001101001…
…100110110011101111011001
3121012100212200210220110001121
4130011201221212303233121
5112142313230442322131
61114414341013245241
735006250266135212
oct3405415146635731
9535325623813047
10123525031214041
11363a4742913a36
1211a2bb8b033821
1353c048bc1c5a2
14227090173a409
15e432822b8911
hex7058699b3bd9

123525031214041 has 2 divisors, whose sum is σ = 123525031214042. Its totient is φ = 123525031214040.

The previous prime is 123525031213999. The next prime is 123525031214089. The reversal of 123525031214041 is 140412130525321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113538167174041 + 9986864040000 = 10655429^2 + 3160200^2 .

It is a cyclic number.

It is not a de Polignac number, because 123525031214041 - 217 = 123525031082969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123525031213988 and 123525031214006.

It is not a weakly prime, because it can be changed into another prime (123525031214941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61762515607020 + 61762515607021.

It is an arithmetic number, because the mean of its divisors is an integer number (61762515607021).

Almost surely, 2123525031214041 is an apocalyptic number.

It is an amenable number.

123525031214041 is a deficient number, since it is larger than the sum of its proper divisors (1).

123525031214041 is an equidigital number, since it uses as much as digits as its factorization.

123525031214041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 123525031214041 its reverse (140412130525321), we get a palindrome (263937161739362).

The spelling of 123525031214041 in words is "one hundred twenty-three trillion, five hundred twenty-five billion, thirty-one million, two hundred fourteen thousand, forty-one".