Search a number
-
+
12384494141941 is a prime number
BaseRepresentation
bin1011010000110111110101…
…0111111100000111110101
31121211221112200122021022001
42310031331113330013311
53110401421000020231
642201205201535301
72415515211211165
oct264157527740765
947757480567261
1012384494141941
113a45264097579
121480246044531
136bab1175858c
1430b5ac6bc5a5
151672383d0b61
hexb437d5fc1f5

12384494141941 has 2 divisors, whose sum is σ = 12384494141942. Its totient is φ = 12384494141940.

The previous prime is 12384494141927. The next prime is 12384494141977. The reversal of 12384494141941 is 14914149448321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10680176946916 + 1704317195025 = 3268054^2 + 1305495^2 .

It is a cyclic number.

It is not a de Polignac number, because 12384494141941 - 213 = 12384494133749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12384494144941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6192247070970 + 6192247070971.

It is an arithmetic number, because the mean of its divisors is an integer number (6192247070971).

Almost surely, 212384494141941 is an apocalyptic number.

It is an amenable number.

12384494141941 is a deficient number, since it is larger than the sum of its proper divisors (1).

12384494141941 is an equidigital number, since it uses as much as digits as its factorization.

12384494141941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3981312, while the sum is 55.

The spelling of 12384494141941 in words is "twelve trillion, three hundred eighty-four billion, four hundred ninety-four million, one hundred forty-one thousand, nine hundred forty-one".