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12384662863117 is a prime number
BaseRepresentation
bin1011010000111000011101…
…1011100011110100001101
31121211221222110010012020111
42310032013123203310031
53110402242143104432
642201234030120021
72415522330262516
oct264160733436415
947757873105214
1012384662863117
113a45340356266
121480292650011
136bab3a6b07ac
1430b5c6c7ba0d
1516724810c347
hexb43876e3d0d

12384662863117 has 2 divisors, whose sum is σ = 12384662863118. Its totient is φ = 12384662863116.

The previous prime is 12384662863061. The next prime is 12384662863163. The reversal of 12384662863117 is 71136826648321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12346692053796 + 37970809321 = 3513786^2 + 194861^2 .

It is a cyclic number.

It is not a de Polignac number, because 12384662863117 - 211 = 12384662861069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12384662863187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6192331431558 + 6192331431559.

It is an arithmetic number, because the mean of its divisors is an integer number (6192331431559).

Almost surely, 212384662863117 is an apocalyptic number.

It is an amenable number.

12384662863117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12384662863117 is an equidigital number, since it uses as much as digits as its factorization.

12384662863117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13934592, while the sum is 58.

The spelling of 12384662863117 in words is "twelve trillion, three hundred eighty-four billion, six hundred sixty-two million, eight hundred sixty-three thousand, one hundred seventeen".