Base | Representation |
---|---|
bin | 11100001010101101101001… |
… | …011101100100000100010101 |
3 | 121020121221211111122202010021 |
4 | 130022231221131210010111 |
5 | 112214133313313413432 |
6 | 1115250214110025141 |
7 | 35044100221023514 |
oct | 3412555135440425 |
9 | 536557744582107 |
10 | 123881511076117 |
11 | 365219434665a3 |
12 | 11a890974a81b1 |
13 | 5417c9010a912 |
14 | 2283c7ba1067b |
15 | e4c698141697 |
hex | 70ab69764115 |
123881511076117 has 2 divisors, whose sum is σ = 123881511076118. Its totient is φ = 123881511076116.
The previous prime is 123881511076091. The next prime is 123881511076163. The reversal of 123881511076117 is 711670115188321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103297423369156 + 20584087706961 = 10163534^2 + 4536969^2 .
It is a cyclic number.
It is not a de Polignac number, because 123881511076117 - 215 = 123881511043349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123881511076717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61940755538058 + 61940755538059.
It is an arithmetic number, because the mean of its divisors is an integer number (61940755538059).
Almost surely, 2123881511076117 is an apocalyptic number.
It is an amenable number.
123881511076117 is a deficient number, since it is larger than the sum of its proper divisors (1).
123881511076117 is an equidigital number, since it uses as much as digits as its factorization.
123881511076117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 564480, while the sum is 52.
The spelling of 123881511076117 in words is "one hundred twenty-three trillion, eight hundred eighty-one billion, five hundred eleven million, seventy-six thousand, one hundred seventeen".
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