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123958425600157 is a prime number
BaseRepresentation
bin11100001011110101010001…
…111011001100000010011101
3121020220022100210220101210211
4130023311101323030002131
5112221413323423201112
61115345414203132421
735052462225501421
oct3413652173140235
9536808323811724
10123958425600157
1136551522730945
1211a9bb81b14111
1354222c9c314c5
142287896a92b81
15e4e69a7d50a7
hex70bd51ecc09d

123958425600157 has 2 divisors, whose sum is σ = 123958425600158. Its totient is φ = 123958425600156.

The previous prime is 123958425599999. The next prime is 123958425600169. The reversal of 123958425600157 is 751006524859321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115573121244036 + 8385304356121 = 10750494^2 + 2895739^2 .

It is a cyclic number.

It is not a de Polignac number, because 123958425600157 - 219 = 123958425075869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123958425600557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61979212800078 + 61979212800079.

It is an arithmetic number, because the mean of its divisors is an integer number (61979212800079).

It is a 2-persistent number, because it is pandigital, and so is 2⋅123958425600157 = 247916851200314, but 3⋅123958425600157 = 371875276800471 is not.

Almost surely, 2123958425600157 is an apocalyptic number.

It is an amenable number.

123958425600157 is a deficient number, since it is larger than the sum of its proper divisors (1).

123958425600157 is an equidigital number, since it uses as much as digits as its factorization.

123958425600157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144000, while the sum is 58.

The spelling of 123958425600157 in words is "one hundred twenty-three trillion, nine hundred fifty-eight billion, four hundred twenty-five million, six hundred thousand, one hundred fifty-seven".