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12399145481 is a prime number
BaseRepresentation
bin10111000110000101…
…11111001000001001
31012000010011212000102
423203002333020021
5200343140123411
65410204415145
7616155666122
oct134302771011
935003155012
1012399145481
115292aa3578
1224a05474b5
131227a67198
14858a3d049
154c8815d3b
hex2e30bf209

12399145481 has 2 divisors, whose sum is σ = 12399145482. Its totient is φ = 12399145480.

The previous prime is 12399145469. The next prime is 12399145501. The reversal of 12399145481 is 18454199321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12352099600 + 47045881 = 111140^2 + 6859^2 .

It is an emirp because it is prime and its reverse (18454199321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12399145481 - 218 = 12398883337 is a prime.

It is a super-2 number, since 2×123991454812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12399145441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6199572740 + 6199572741.

It is an arithmetic number, because the mean of its divisors is an integer number (6199572741).

Almost surely, 212399145481 is an apocalyptic number.

It is an amenable number.

12399145481 is a deficient number, since it is larger than the sum of its proper divisors (1).

12399145481 is an equidigital number, since it uses as much as digits as its factorization.

12399145481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 311040, while the sum is 47.

The spelling of 12399145481 in words is "twelve billion, three hundred ninety-nine million, one hundred forty-five thousand, four hundred eighty-one".