1240012525453 has 4 divisors (see below), whose sum is σ = 1335398104348. Its totient is φ = 1144626946560.

The previous prime is 1240012525441. The next prime is 1240012525483. The reversal of 1240012525453 is 3545252100421.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 281937636484 + 958074888969 = 530978^2 + 978813^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240012525453 - 2⁵ = 1240012525421 is a prime.

It is a super-3 number, since 3×1240012525453³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240012525483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47692789428 + ... + 47692789453.

It is an arithmetic number, because the mean of its divisors is an integer number (333849526087).

Almost surely, 2^{1240012525453} is an apocalyptic number.

1240012525453 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1240012525453 is a deficient number, since it is larger than the sum of its proper divisors (95385578895).

1240012525453 is an equidigital number, since it uses as much as digits as its factorization.

1240012525453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95385578894.

The product of its (nonzero) digits is 48000, while the sum is 34.

Adding to 1240012525453 its reverse (3545252100421), we get a palindrome (4785264625874).

The spelling of 1240012525453 in words is "one trillion, two hundred forty billion, twelve million, five hundred twenty-five thousand, four hundred fifty-three".