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124001433230 = 25103120389741
BaseRepresentation
bin111001101111100001…
…1111011011010001110
3102212001212120110222012
41303133003323122032
54012423331330410
6132544313021222
711646604535333
oct1633703733216
9385055513865
10124001433230
1148652638134
12200479b4812
13b9021bb23c
14600495098a
15335b410605
hex1cdf0fb68e

124001433230 has 16 divisors (see below), whose sum is σ = 225369597024. Its totient is φ = 49119013920.

The previous prime is 124001433221. The next prime is 124001433233. The reversal of 124001433230 is 32334100421.

It is a junction number, because it is equal to n+sod(n) for n = 124001433196 and 124001433205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124001433233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60193841 + ... + 60195900.

It is an arithmetic number, because the mean of its divisors is an integer number (14085599814).

Almost surely, 2124001433230 is an apocalyptic number.

124001433230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

124001433230 is a deficient number, since it is larger than the sum of its proper divisors (101368163794).

124001433230 is a wasteful number, since it uses less digits than its factorization.

124001433230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120389851.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 124001433230 its reverse (32334100421), we get a palindrome (156335533651).

The spelling of 124001433230 in words is "one hundred twenty-four billion, one million, four hundred thirty-three thousand, two hundred thirty".

Divisors: 1 2 5 10 103 206 515 1030 120389741 240779482 601948705 1203897410 12400143323 24800286646 62000716615 124001433230