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124002131403133 is a prime number
BaseRepresentation
bin11100001100011101111110…
…111111100110000101111101
3121021001111011202002020022101
4130030131332333212011331
5112223122331114400013
61115421443122145101
735055600261625504
oct3414357677460575
9537044152066271
10124002131403133
11365690104a2575
1211aa853aab2191
135426473989a99
142289a414b183b
15e508a77cc8dd
hex70c77efe617d

124002131403133 has 2 divisors, whose sum is σ = 124002131403134. Its totient is φ = 124002131403132.

The previous prime is 124002131403127. The next prime is 124002131403149. The reversal of 124002131403133 is 331304131200421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118319614660324 + 5682516742809 = 10877482^2 + 2383803^2 .

It is an emirp because it is prime and its reverse (331304131200421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 124002131403133 - 213 = 124002131394941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124002131403103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62001065701566 + 62001065701567.

It is an arithmetic number, because the mean of its divisors is an integer number (62001065701567).

Almost surely, 2124002131403133 is an apocalyptic number.

It is an amenable number.

124002131403133 is a deficient number, since it is larger than the sum of its proper divisors (1).

124002131403133 is an equidigital number, since it uses as much as digits as its factorization.

124002131403133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 124002131403133 its reverse (331304131200421), we get a palindrome (455306262603554).

The spelling of 124002131403133 in words is "one hundred twenty-four trillion, two billion, one hundred thirty-one million, four hundred three thousand, one hundred thirty-three".