Base | Representation |
---|---|
bin | 11100001100100001001001… |
… | …101000100001100110001001 |
3 | 121021001210221200021021011111 |
4 | 130030201021220201212021 |
5 | 112223201311432131444 |
6 | 1115423204330130321 |
7 | 35056050443055406 |
oct | 3414411150414611 |
9 | 537053850237144 |
10 | 124005531130249 |
11 | 3656a4a55618aa |
12 | 11aa91295809a1 |
13 | 5426896118632 |
14 | 2289c84c0b2ad |
15 | e50a05ece234 |
hex | 70c849a21989 |
124005531130249 has 2 divisors, whose sum is σ = 124005531130250. Its totient is φ = 124005531130248.
The previous prime is 124005531130231. The next prime is 124005531130277. The reversal of 124005531130249 is 942031135500421.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112167162810000 + 11838368320249 = 10590900^2 + 3440693^2 .
It is a cyclic number.
It is not a de Polignac number, because 124005531130249 - 219 = 124005530605961 is a prime.
It is not a weakly prime, because it can be changed into another prime (124005531130219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62002765565124 + 62002765565125.
It is an arithmetic number, because the mean of its divisors is an integer number (62002765565125).
Almost surely, 2124005531130249 is an apocalyptic number.
It is an amenable number.
124005531130249 is a deficient number, since it is larger than the sum of its proper divisors (1).
124005531130249 is an equidigital number, since it uses as much as digits as its factorization.
124005531130249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 124005531130249 in words is "one hundred twenty-four trillion, five billion, five hundred thirty-one million, one hundred thirty thousand, two hundred forty-nine".
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