Search a number
-
+
1240110133 is a prime number
BaseRepresentation
bin100100111101010…
…1001010000110101
310012102111010021221
41021322221100311
510014432011013
6323015510341
742505522303
oct11172512065
93172433257
101240110133
11587012109
122a73883b1
13169bc91a2
14ba9b1273
1573d1008d
hex49ea9435

1240110133 has 2 divisors, whose sum is σ = 1240110134. Its totient is φ = 1240110132.

The previous prime is 1240110127. The next prime is 1240110197. The reversal of 1240110133 is 3310110421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1102704849 + 137405284 = 33207^2 + 11722^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240110133 - 29 = 1240109621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240110433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620055066 + 620055067.

It is an arithmetic number, because the mean of its divisors is an integer number (620055067).

Almost surely, 21240110133 is an apocalyptic number.

It is an amenable number.

1240110133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240110133 is an equidigital number, since it uses as much as digits as its factorization.

1240110133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1240110133 is about 35215.1974721142. The cubic root of 1240110133 is about 1074.3688764895.

Adding to 1240110133 its reverse (3310110421), we get a palindrome (4550220554).

The spelling of 1240110133 in words is "one billion, two hundred forty million, one hundred ten thousand, one hundred thirty-three".