Base | Representation |
---|---|
bin | 111001101111110110… |
… | …1100010100001010011 |
3 | 102212002122002200001221 |
4 | 1303133231202201103 |
5 | 4012434124410311 |
6 | 132545342505511 |
7 | 11650066336354 |
oct | 1633755424123 |
9 | 385078080057 |
10 | 124012341331 |
11 | 4865880859a |
12 | 2004b595297 |
13 | b90453a238 |
14 | 600618dd2b |
15 | 335c367671 |
hex | 1cdfb62853 |
124012341331 has 2 divisors, whose sum is σ = 124012341332. Its totient is φ = 124012341330.
The previous prime is 124012341307. The next prime is 124012341371. The reversal of 124012341331 is 133143210421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 124012341331 - 219 = 124011817043 is a prime.
It is a super-2 number, since 2×1240123413312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124012341296 and 124012341305.
It is not a weakly prime, because it can be changed into another prime (124012341371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62006170665 + 62006170666.
It is an arithmetic number, because the mean of its divisors is an integer number (62006170666).
Almost surely, 2124012341331 is an apocalyptic number.
124012341331 is a deficient number, since it is larger than the sum of its proper divisors (1).
124012341331 is an equidigital number, since it uses as much as digits as its factorization.
124012341331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 124012341331 its reverse (133143210421), we get a palindrome (257155551752).
The spelling of 124012341331 in words is "one hundred twenty-four billion, twelve million, three hundred forty-one thousand, three hundred thirty-one".
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