Base | Representation |
---|---|
bin | 11100001100101000001000… |
… | …101110001010000110010111 |
3 | 121021002112022102112001211202 |
4 | 130030220020232022012113 |
5 | 112223312142144204143 |
6 | 1115430444520223115 |
7 | 35056434353435615 |
oct | 3414501056120627 |
9 | 537075272461752 |
10 | 124013032022423 |
11 | 365726a4622145 |
12 | 11aaa68160aa9b |
13 | 54274c012977b |
14 | 228a3970b26b5 |
15 | e50ce478aab8 |
hex | 70ca08b8a197 |
124013032022423 has 2 divisors, whose sum is σ = 124013032022424. Its totient is φ = 124013032022422.
The previous prime is 124013032022357. The next prime is 124013032022443. The reversal of 124013032022423 is 324220230310421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124013032022423 - 210 = 124013032021399 is a prime.
It is a super-2 number, since 2×1240130320224232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124013032022443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62006516011211 + 62006516011212.
It is an arithmetic number, because the mean of its divisors is an integer number (62006516011212).
Almost surely, 2124013032022423 is an apocalyptic number.
124013032022423 is a deficient number, since it is larger than the sum of its proper divisors (1).
124013032022423 is an equidigital number, since it uses as much as digits as its factorization.
124013032022423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 124013032022423 its reverse (324220230310421), we get a palindrome (448233262332844).
The spelling of 124013032022423 in words is "one hundred twenty-four trillion, thirteen billion, thirty-two million, twenty-two thousand, four hundred twenty-three".
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