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1240134341 is a prime number
BaseRepresentation
bin100100111101010…
…1111001011000101
310012102112100111112
41021322233023011
510014433244331
6323020214405
742505653005
oct11172571305
93172470445
101240134341
11587029316
122a739a405
13169c07204
14ba9ba005
1573d1732b
hex49eaf2c5

1240134341 has 2 divisors, whose sum is σ = 1240134342. Its totient is φ = 1240134340.

The previous prime is 1240134307. The next prime is 1240134383. The reversal of 1240134341 is 1434310421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1211736100 + 28398241 = 34810^2 + 5329^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240134341 - 222 = 1235940037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240134041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620067170 + 620067171.

It is an arithmetic number, because the mean of its divisors is an integer number (620067171).

Almost surely, 21240134341 is an apocalyptic number.

It is an amenable number.

1240134341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240134341 is an equidigital number, since it uses as much as digits as its factorization.

1240134341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1240134341 is about 35215.5411856754. The cubic root of 1240134341 is about 1074.3758673074.

Adding to 1240134341 its reverse (1434310421), we get a palindrome (2674444762).

The spelling of 1240134341 in words is "one billion, two hundred forty million, one hundred thirty-four thousand, three hundred forty-one".